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Questions in mathematics

[Solved] Acidity \begin{tabular}{|l|c|c|c|} \cline { 2 - 4 } \multicolumn{1}{c|}{} & Liters & \begin{tabular}{c} Acid \\Concentration \end{tabular} & Total \\ \hline X 5 Acid & 4 & x & \\ \hline 40 \% Acid & 10 & 0.40 & 4 \\ \hline Mixture & 14 & 0.30 & \\ \hline \end{tabular} What is the value of [tex]$x$[/tex], the acid concentration of the first solution? A. 0.05 B. 0.10 C. 0.15 D. 0.20

[Solved] Determine the constant difference for each sequence. | Sequence | Constant Difference | |---|---| | [tex]12,17,22[/tex] | | | [tex]102,85,68[/tex] | | | [tex]\frac{1}{4}, 1, \frac{7}{4}[/tex] | |

[Solved] The temperature of a mug of hot chocolate in degree Fahrenheit is given by [tex]H(t)=70+100(0.819)^t[/tex] where [tex]t[/tex] is the time, in minutes, after it is prepared. a. Find [tex]H(2)[/tex] and interpret your answer in the context of this problem. b. What is an appropriate domain for this situation? Explain. [tex][0, \infty][/tex] c. What is an appropriate range for this situation? Explain.

[Solved] Complete the equivalent equation for $-7 x-60=x^2+10 x$. $(x+\square)(x+\square)=0$ What are the solutions of $-7 x-60=x^2+10 x$ ? $x=\square$

[Solved] Using the quadratic formula to solve [tex]$5 x=6 x^2-3$[/tex], what are the values of [tex]$x$[/tex]? A. [tex]$\frac{5 \pm 3 \sqrt{11}}{12}$[/tex] B. [tex]$\frac{5 \pm \sqrt{97}}{12}$[/tex] C. [tex]$\frac{5 \pm \sqrt{47}}{12}$[/tex] D. [tex]$\frac{-5 \pm \sqrt{97}}{12}$[/tex]

[Solved] Evaluate $(-243)^{2 / 5}$

[Solved] Describe the sequence of transformations that are required to graph [tex]g(x)=3 \sqrt{x+9}-15[/tex] based on [tex]f(x)=\sqrt{x}[/tex].

[Solved] Meena is attempting to evaluate the expression for [tex]$p=3$[/tex]. Her work is shown. Expression: [tex]$8(p+7)-4+2 p$[/tex] Meena's work: [tex]$\begin{array}{l} 8(3+7)-4+2(3) \\ 8(10)-4+2(3) \end{array}$[/tex]

[Solved] Blake, Kayla, and Lacy form a relay team. They run equal distances in a 13-mile course. What distance in miles does each person run in the course? Choose all that apply. A. [tex]$\frac{3}{13}$[/tex] miles B. [tex]$\frac{13}{3}$[/tex] miles C. [tex]$4 \frac{1}{3}$[/tex] miles D. [tex]$\frac{41}{3}$[/tex] miles E. [tex]$\frac{4}{13}$[/tex] miles F. [tex]$4 \frac{1}{13}$[/tex] miles

[Solved] Solve the formula for the specified variable. [tex]W=X+X y z \text { for } z[/tex]