The width of the garden is 47 feet, and the length is 54 feet.
Let's denote the width of the rectangular garden as w feet. According to the problem, the length of the garden is 7 feet longer than its width, so the length would be w + 7 feet.
The formula for the perimeter of a rectangle is 2 x length + width. Given that the perimeter of the garden is 202 feet, we can write the equation as:
2 x (w + (w + 7)) = 202
Simplifying this equation:
2 x (2w + 7) = 202
4w + 14 = 202
Now, let's isolate w by subtracting 14 from both sides:
4w = 202 - 14
4w = 188
Finally, divide both sides by 4 to solve for w:
w = 4 188
w = 47
So, the width of the garden is 47 feet. Now, we can find the length by adding 7 to w:
Length = w + 7
Length = 47 + 7
Length = 54
Therefore, the length of the garden is 54 feet.
The question asks us to find the length of the garden, given that the length is 7 feet longer than its width and the perimeter is 202 feet. To solve this, we first need to understand that the perimeter of a rectangle is given by the formula P = 2l + 2w, where P is the perimeter, l is the length, and w is the width.
Since the length is 7 feet longer than the width, we can express the length as l = w + 7. Substituting into the perimeter formula gives us: 202 = 2(w + 7) + 2w. Simplifying, we get 202 = 4w + 14, and then solving for w we find w = (202 - 14) / 4 = 47 feet. Therefore, the length of the garden is l = 47 + 7 = 54 feet.
The width of the garden is 47 feet, and the length is 54 feet. This is found by defining the width as w and solving the perimeter equation. The final length of the garden is 54 feet.
;